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// { dg-do compile }
// Perform access checking to parameter and return type of
// function template correctly when only specialization is friend.
template <class T>
typename T::Inner
foo () {
return typename T::Inner();
}
class Outer {
private:
struct Inner {};
friend Outer::Inner foo<Outer> ();
};
void f() {
foo<Outer>();
}
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