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-<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /><title>Implementation</title><meta name="generator" content="DocBook XSL-NS Stylesheets V1.77.1" /><meta name="keywords" content="ISO C++, allocator" /><meta name="keywords" content="ISO C++, library" /><meta name="keywords" content="ISO C++, runtime, library" /><link rel="home" href="../index.html" title="The GNU C++ Library" /><link rel="up" href="bitmap_allocator.html" title="Chapter 21. The bitmap_allocator" /><link rel="prev" href="bitmap_allocator.html" title="Chapter 21. The bitmap_allocator" /><link rel="next" href="policy_data_structures.html" title="Chapter 22. Policy-Based Data Structures" /></head><body><div class="navheader"><table width="100%" summary="Navigation header"><tr><th colspan="3" align="center">Implementation</th></tr><tr><td width="20%" align="left"><a accesskey="p" href="bitmap_allocator.html">Prev</a> </td><th width="60%" align="center">Chapter 21. The bitmap_allocator</th><td width="20%" align="right"> <a accesskey="n" href="policy_data_structures.html">Next</a></td></tr></table><hr /></div><div class="section"><div class="titlepage"><div><div><h2 class="title" style="clear: both"><a id="allocator.bitmap.impl"></a>Implementation</h2></div></div></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.free_list_store"></a>Free List Store</h3></div></div></div><p>
- The Free List Store (referred to as FLS for the remaining part of this
- document) is the Global memory pool that is shared by all instances of
- the bitmapped allocator instantiated for any type. This maintains a
- sorted order of all free memory blocks given back to it by the
- bitmapped allocator, and is also responsible for giving memory to the
- bitmapped allocator when it asks for more.
- </p><p>
- Internally, there is a Free List threshold which indicates the
- Maximum number of free lists that the FLS can hold internally
- (cache). Currently, this value is set at 64. So, if there are
- more than 64 free lists coming in, then some of them will be given
- back to the OS using operator delete so that at any given time the
- Free List's size does not exceed 64 entries. This is done because
- a Binary Search is used to locate an entry in a free list when a
- request for memory comes along. Thus, the run-time complexity of
- the search would go up given an increasing size, for 64 entries
- however, lg(64) == 6 comparisons are enough to locate the correct
- free list if it exists.
- </p><p>
- Suppose the free list size has reached its threshold, then the
- largest block from among those in the list and the new block will
- be selected and given back to the OS. This is done because it
- reduces external fragmentation, and allows the OS to use the
- larger blocks later in an orderly fashion, possibly merging them
- later. Also, on some systems, large blocks are obtained via calls
- to mmap, so giving them back to free system resources becomes most
- important.
- </p><p>
- The function _S_should_i_give decides the policy that determines
- whether the current block of memory should be given to the
- allocator for the request that it has made. That's because we may
- not always have exact fits for the memory size that the allocator
- requests. We do this mainly to prevent external fragmentation at
- the cost of a little internal fragmentation. Now, the value of
- this internal fragmentation has to be decided by this function. I
- can see 3 possibilities right now. Please add more as and when you
- find better strategies.
- </p><div class="orderedlist"><ol class="orderedlist" type="1"><li class="listitem"><p>Equal size check. Return true only when the 2 blocks are of equal
-size.</p></li><li class="listitem"><p>Difference Threshold: Return true only when the _block_size is
-greater than or equal to the _required_size, and if the _BS is &gt; _RS
-by a difference of less than some THRESHOLD value, then return true,
-else return false. </p></li><li class="listitem"><p>Percentage Threshold. Return true only when the _block_size is
-greater than or equal to the _required_size, and if the _BS is &gt; _RS
-by a percentage of less than some THRESHOLD value, then return true,
-else return false.</p></li></ol></div><p>
- Currently, (3) is being used with a value of 36% Maximum wastage per
- Super Block.
- </p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.super_block"></a>Super Block</h3></div></div></div><p>
- A super block is the block of memory acquired from the FLS from
- which the bitmap allocator carves out memory for single objects
- and satisfies the user's requests. These super blocks come in
- sizes that are powers of 2 and multiples of 32
- (_Bits_Per_Block). Yes both at the same time! That's because the
- next super block acquired will be 2 times the previous one, and
- also all super blocks have to be multiples of the _Bits_Per_Block
- value.
- </p><p>
- How does it interact with the free list store?
- </p><p>
- The super block is contained in the FLS, and the FLS is responsible for
- getting / returning Super Bocks to and from the OS using operator new
- as defined by the C++ standard.
- </p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.super_block_data"></a>Super Block Data Layout</h3></div></div></div><p>
- Each Super Block will be of some size that is a multiple of the
- number of Bits Per Block. Typically, this value is chosen as
- Bits_Per_Byte x sizeof(size_t). On an x86 system, this gives the
- figure 8 x 4 = 32. Thus, each Super Block will be of size 32
- x Some_Value. This Some_Value is sizeof(value_type). For now, let
- it be called 'K'. Thus, finally, Super Block size is 32 x K bytes.
- </p><p>
- This value of 32 has been chosen because each size_t has 32-bits
- and Maximum use of these can be made with such a figure.
- </p><p>
- Consider a block of size 64 ints. In memory, it would look like this:
- (assume a 32-bit system where, size_t is a 32-bit entity).
- </p><div class="table"><a id="idp17500848"></a><p class="title"><strong>Table 21.1. Bitmap Allocator Memory Map</strong></p><div class="table-contents"><table summary="Bitmap Allocator Memory Map" border="1"><colgroup><col align="left" class="c1" /><col align="left" class="c2" /><col align="left" class="c3" /><col align="left" class="c4" /><col align="left" class="c5" /></colgroup><tbody><tr><td align="left">268</td><td align="left">0</td><td align="left">4294967295</td><td align="left">4294967295</td><td align="left">Data -&gt; Space for 64 ints</td></tr></tbody></table></div></div><br class="table-break" /><p>
- The first Column(268) represents the size of the Block in bytes as
- seen by the Bitmap Allocator. Internally, a global free list is
- used to keep track of the free blocks used and given back by the
- bitmap allocator. It is this Free List Store that is responsible
- for writing and managing this information. Actually the number of
- bytes allocated in this case would be: 4 + 4 + (4x2) + (64x4) =
- 272 bytes, but the first 4 bytes are an addition by the Free List
- Store, so the Bitmap Allocator sees only 268 bytes. These first 4
- bytes about which the bitmapped allocator is not aware hold the
- value 268.
- </p><p>
- What do the remaining values represent?</p><p>
- The 2nd 4 in the expression is the sizeof(size_t) because the
- Bitmapped Allocator maintains a used count for each Super Block,
- which is initially set to 0 (as indicated in the diagram). This is
- incremented every time a block is removed from this super block
- (allocated), and decremented whenever it is given back. So, when
- the used count falls to 0, the whole super block will be given
- back to the Free List Store.
- </p><p>
- The value 4294967295 represents the integer corresponding to the bit
- representation of all bits set: 11111111111111111111111111111111.
- </p><p>
- The 3rd 4x2 is size of the bitmap itself, which is the size of 32-bits
- x 2,
- which is 8-bytes, or 2 x sizeof(size_t).
- </p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.max_wasted"></a>Maximum Wasted Percentage</h3></div></div></div><p>
- This has nothing to do with the algorithm per-se,
- only with some vales that must be chosen correctly to ensure that the
- allocator performs well in a real word scenario, and maintains a good
- balance between the memory consumption and the allocation/deallocation
- speed.
- </p><p>
- The formula for calculating the maximum wastage as a percentage:
- </p><p>
-(32 x k + 1) / (2 x (32 x k + 1 + 32 x c)) x 100.
- </p><p>
- where k is the constant overhead per node (e.g., for list, it is
- 8 bytes, and for map it is 12 bytes) and c is the size of the
- base type on which the map/list is instantiated. Thus, suppose the
- type1 is int and type2 is double, they are related by the relation
- sizeof(double) == 2*sizeof(int). Thus, all types must have this
- double size relation for this formula to work properly.
- </p><p>
- Plugging-in: For List: k = 8 and c = 4 (int and double), we get:
- 33.376%
- </p><p>
-For map/multimap: k = 12, and c = 4 (int and double), we get: 37.524%
- </p><p>
- Thus, knowing these values, and based on the sizeof(value_type), we may
- create a function that returns the Max_Wastage_Percentage for us to use.
- </p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.allocate"></a><code class="function">allocate</code></h3></div></div></div><p>
- The allocate function is specialized for single object allocation
- ONLY. Thus, ONLY if n == 1, will the bitmap_allocator's
- specialized algorithm be used. Otherwise, the request is satisfied
- directly by calling operator new.
- </p><p>
- Suppose n == 1, then the allocator does the following:
- </p><div class="orderedlist"><ol class="orderedlist" type="1"><li class="listitem"><p>
- Checks to see whether a free block exists somewhere in a region
- of memory close to the last satisfied request. If so, then that
- block is marked as allocated in the bit map and given to the
- user. If not, then (2) is executed.
- </p></li><li class="listitem"><p>
- Is there a free block anywhere after the current block right
- up to the end of the memory that we have? If so, that block is
- found, and the same procedure is applied as above, and
- returned to the user. If not, then (3) is executed.
- </p></li><li class="listitem"><p>
- Is there any block in whatever region of memory that we own
- free? This is done by checking
- </p><div class="itemizedlist"><ul class="itemizedlist" style="list-style-type: disc; "><li class="listitem"><p>
- The use count for each super block, and if that fails then
- </p></li><li class="listitem"><p>
- The individual bit-maps for each super block.
- </p></li></ul></div><p>
- Note: Here we are never touching any of the memory that the
- user will be given, and we are confining all memory accesses
- to a small region of memory! This helps reduce cache
- misses. If this succeeds then we apply the same procedure on
- that bit-map as (1), and return that block of memory to the
- user. However, if this process fails, then we resort to (4).
- </p></li><li class="listitem"><p>
- This process involves Refilling the internal exponentially
- growing memory pool. The said effect is achieved by calling
- _S_refill_pool which does the following:
- </p><div class="itemizedlist"><ul class="itemizedlist" style="list-style-type: disc; "><li class="listitem"><p>
- Gets more memory from the Global Free List of the Required
- size.
- </p></li><li class="listitem"><p>
- Adjusts the size for the next call to itself.
- </p></li><li class="listitem"><p>
- Writes the appropriate headers in the bit-maps.
- </p></li><li class="listitem"><p>
- Sets the use count for that super-block just allocated to 0
- (zero).
- </p></li><li class="listitem"><p>
- All of the above accounts to maintaining the basic invariant
- for the allocator. If the invariant is maintained, we are
- sure that all is well. Now, the same process is applied on
- the newly acquired free blocks, which are dispatched
- accordingly.
- </p></li></ul></div></li></ol></div><p>
-Thus, you can clearly see that the allocate function is nothing but a
-combination of the next-fit and first-fit algorithm optimized ONLY for
-single object allocations.
-</p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.deallocate"></a><code class="function">deallocate</code></h3></div></div></div><p>
- The deallocate function again is specialized for single objects ONLY.
- For all n belonging to &gt; 1, the operator delete is called without
- further ado, and the deallocate function returns.
- </p><p>
- However for n == 1, a series of steps are performed:
- </p><div class="orderedlist"><ol class="orderedlist" type="1"><li class="listitem"><p>
- We first need to locate that super-block which holds the memory
- location given to us by the user. For that purpose, we maintain
- a static variable _S_last_dealloc_index, which holds the index
- into the vector of block pairs which indicates the index of the
- last super-block from which memory was freed. We use this
- strategy in the hope that the user will deallocate memory in a
- region close to what he/she deallocated the last time around. If
- the check for belongs_to succeeds, then we determine the bit-map
- for the given pointer, and locate the index into that bit-map,
- and mark that bit as free by setting it.
- </p></li><li class="listitem"><p>
- If the _S_last_dealloc_index does not point to the memory block
- that we're looking for, then we do a linear search on the block
- stored in the vector of Block Pairs. This vector in code is
- called _S_mem_blocks. When the corresponding super-block is
- found, we apply the same procedure as we did for (1) to mark the
- block as free in the bit-map.
- </p></li></ol></div><p>
- Now, whenever a block is freed, the use count of that particular
- super block goes down by 1. When this use count hits 0, we remove
- that super block from the list of all valid super blocks stored in
- the vector. While doing this, we also make sure that the basic
- invariant is maintained by making sure that _S_last_request and
- _S_last_dealloc_index point to valid locations within the vector.
- </p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.questions"></a>Questions</h3></div></div></div><div class="section"><div class="titlepage"><div><div><h4 class="title"><a id="bitmap.impl.question.1"></a>1</h4></div></div></div><p>
-Q1) The "Data Layout" section is
-cryptic. I have no idea of what you are trying to say. Layout of what?
-The free-list? Each bitmap? The Super Block?
- </p><p>
- The layout of a Super Block of a given
-size. In the example, a super block of size 32 x 1 is taken. The
-general formula for calculating the size of a super block is
-32 x sizeof(value_type) x 2^n, where n ranges from 0 to 32 for 32-bit
-systems.
- </p></div><div class="section"><div class="titlepage"><div><div><h4 class="title"><a id="bitmap.impl.question.2"></a>2</h4></div></div></div><p>
- And since I just mentioned the
-term `each bitmap', what in the world is meant by it? What does each
-bitmap manage? How does it relate to the super block? Is the Super
-Block a bitmap as well?
- </p><p>
- Each bitmap is part of a Super Block which is made up of 3 parts
- as I have mentioned earlier. Re-iterating, 1. The use count,
- 2. The bit-map for that Super Block. 3. The actual memory that
- will be eventually given to the user. Each bitmap is a multiple
- of 32 in size. If there are 32 x (2^3) blocks of single objects
- to be given, there will be '32 x (2^3)' bits present. Each 32
- bits managing the allocated / free status for 32 blocks. Since
- each size_t contains 32-bits, one size_t can manage up to 32
- blocks' status. Each bit-map is made up of a number of size_t,
- whose exact number for a super-block of a given size I have just
- mentioned.
- </p></div><div class="section"><div class="titlepage"><div><div><h4 class="title"><a id="bitmap.impl.question.3"></a>3</h4></div></div></div><p>
- How do the allocate and deallocate functions work in regard to
- bitmaps?
- </p><p>
- The allocate and deallocate functions manipulate the bitmaps and
- have nothing to do with the memory that is given to the user. As
- I have earlier mentioned, a 1 in the bitmap's bit field
- indicates free, while a 0 indicates allocated. This lets us
- check 32 bits at a time to check whether there is at lease one
- free block in those 32 blocks by testing for equality with
- (0). Now, the allocate function will given a memory block find
- the corresponding bit in the bitmap, and will reset it (i.e.,
- make it re-set (0)). And when the deallocate function is called,
- it will again set that bit after locating it to indicate that
- that particular block corresponding to this bit in the bit-map
- is not being used by anyone, and may be used to satisfy future
- requests.
- </p><p>
- e.g.: Consider a bit-map of 64-bits as represented below:
- 1111111111111111111111111111111111111111111111111111111111111111
- </p><p>
- Now, when the first request for allocation of a single object
- comes along, the first block in address order is returned. And
- since the bit-maps in the reverse order to that of the address
- order, the last bit (LSB if the bit-map is considered as a
- binary word of 64-bits) is re-set to 0.
- </p><p>
- The bit-map now looks like this:
- 1111111111111111111111111111111111111111111111111111111111111110
- </p></div></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.locality"></a>Locality</h3></div></div></div><p>
- Another issue would be whether to keep the all bitmaps in a
- separate area in memory, or to keep them near the actual blocks
- that will be given out or allocated for the client. After some
- testing, I've decided to keep these bitmaps close to the actual
- blocks. This will help in 2 ways.
- </p><div class="orderedlist"><ol class="orderedlist" type="1"><li class="listitem"><p>Constant time access for the bitmap themselves, since no kind of
-look up will be needed to find the correct bitmap list or its
-equivalent.</p></li><li class="listitem"><p>And also this would preserve the cache as far as possible.</p></li></ol></div><p>
- So in effect, this kind of an allocator might prove beneficial from a
- purely cache point of view. But this allocator has been made to try and
- roll out the defects of the node_allocator, wherein the nodes get
- skewed about in memory, if they are not returned in the exact reverse
- order or in the same order in which they were allocated. Also, the
- new_allocator's book keeping overhead is too much for small objects and
- single object allocations, though it preserves the locality of blocks
- very well when they are returned back to the allocator.
- </p></div><div class="section"><div class="titlepage"><div><div><h3 class="title"><a id="bitmap.impl.grow_policy"></a>Overhead and Grow Policy</h3></div></div></div><p>
- Expected overhead per block would be 1 bit in memory. Also, once
- the address of the free list has been found, the cost for
- allocation/deallocation would be negligible, and is supposed to be
- constant time. For these very reasons, it is very important to
- minimize the linear time costs, which include finding a free list
- with a free block while allocating, and finding the corresponding
- free list for a block while deallocating. Therefore, I have
- decided that the growth of the internal pool for this allocator
- will be exponential as compared to linear for
- node_allocator. There, linear time works well, because we are
- mainly concerned with speed of allocation/deallocation and memory
- consumption, whereas here, the allocation/deallocation part does
- have some linear/logarithmic complexity components in it. Thus, to
- try and minimize them would be a good thing to do at the cost of a
- little bit of memory.
- </p><p>
- Another thing to be noted is the pool size will double every time
- the internal pool gets exhausted, and all the free blocks have
- been given away. The initial size of the pool would be
- sizeof(size_t) x 8 which is the number of bits in an integer,
- which can fit exactly in a CPU register. Hence, the term given is
- exponential growth of the internal pool.
- </p></div></div><div class="navfooter"><hr /><table width="100%" summary="Navigation footer"><tr><td width="40%" align="left"><a accesskey="p" href="bitmap_allocator.html">Prev</a> </td><td width="20%" align="center"><a accesskey="u" href="bitmap_allocator.html">Up</a></td><td width="40%" align="right"> <a accesskey="n" href="policy_data_structures.html">Next</a></td></tr><tr><td width="40%" align="left" valign="top">Chapter 21. The bitmap_allocator </td><td width="20%" align="center"><a accesskey="h" href="../index.html">Home</a></td><td width="40%" align="right" valign="top"> Chapter 22. Policy-Based Data Structures</td></tr></table></div></body></html> \ No newline at end of file