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+/*
+ * Copyright (C) 2013 The CyanogenMod Project
+ *
+ * Licensed under the Apache License, Version 2.0 (the "License");
+ * you may not use this file except in compliance with the License.
+ * You may obtain a copy of the License at
+ *
+ * http://www.apache.org/licenses/LICENSE-2.0
+ *
+ * Unless required by applicable law or agreed to in writing, software
+ * distributed under the License is distributed on an "AS IS" BASIS,
+ * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+ * See the License for the specific language governing permissions and
+ * limitations under the License.
+ */
+
+package org.cyanogenmod.wallpapers.photophase.utils;
+
+import android.graphics.Rect;
+import java.util.Stack;
+
+/**
+ * The maximal empty rectangle algorithm that allows to find the rectangle with the maximal
+ * area that could be create in empty areas (in this case 0 in a byte matrix)
+ */
+//
+// Based on the source discussed at http://discuss.leetcode.com/questions/260/maximal-rectangle
+//
+public final class MERAlgorithm {
+
+ /**
+ * Method that returns the maximal empty rectangle (MER) for a matrix of bytes (1/0)
+ *
+ * @param matrix The matrix
+ * @return Rect The maximal empty rectangle
+ */
+ public static Rect getMaximalEmptyRectangle(byte[][] matrix) {
+ // Check matrix
+ int rows = matrix.length;
+ if (rows == 0) return null;
+ int cols = matrix[0].length;
+
+ // Convert to histogram
+ int[][] histogram = toHistogram(matrix);
+
+ // Find the maximal area of every histogram
+ Rect maxRect = new Rect();
+ for (int i = 0; i < rows; ++i) {
+ Rect rect = maximalRectangle(histogram[i], i);
+ if ((maxRect.width() * maxRect.height()) < (rect.width() * rect.height())) {
+ maxRect = rect;
+ }
+ }
+ return ensureBounds(maxRect, cols, rows);
+ }
+
+ /**
+ * Method that ensure the bounds of the max rectangle
+ *
+ * @param rect The rectangle to check
+ * @param cols The number of cols
+ * @param rows The number of rows
+ * @return Rect The rectangle checked
+ */
+ private static Rect ensureBounds(Rect rect, int cols, int rows) {
+ if (rect.right - rect.left >= cols) rect.right = cols;
+ if (rect.bottom - rect.top >= rows) rect.bottom = rows;
+ return rect;
+ }
+
+ /**
+ * Method that returns the maximal rectangle for an histogram of areas
+ *
+ * @return Rect The maximal rectangle histogram/area
+ */
+ @SuppressWarnings("boxing")
+ private static Rect maximalRectangle(int[] histogram, int row) {
+ Stack<Integer> stack = new Stack<Integer>();
+ int length = histogram.length;
+ Rect maxRect = new Rect();
+ int i = 0;
+ while (i < length) {
+ if (stack.isEmpty() || histogram[i] >= histogram[stack.peek()]) {
+ stack.push(i++);
+ } else {
+ Rect rect = new Rect();
+ rect.left = stack.pop();
+ rect.right = rect.left + (stack.isEmpty() ? i : (i - stack.peek() - 1));
+ rect.top = row - histogram[rect.left] + 1;
+ rect.bottom = rect.top + histogram[rect.left];
+ if ((maxRect.width() * maxRect.height()) < (rect.width() * rect.height())) {
+ maxRect = rect;
+ }
+ }
+ }
+ while (!stack.isEmpty()) {
+ Rect rect = new Rect();
+ rect.left = stack.pop();
+ rect.right = rect.left + (stack.isEmpty() ? i : (i - stack.peek() - 1));
+ rect.top = row - histogram[rect.left] + 1;
+ rect.bottom = rect.top + histogram[rect.left];
+ if ((maxRect.width() * maxRect.height()) < (rect.width() * rect.height())) {
+ maxRect = rect;
+ }
+ }
+ return maxRect;
+ }
+
+ /**
+ * Method that converts the empty areas to a histogram
+ *
+ * @param matrix The matrix where to find the MER
+ * return int[][] The histogram of empty areas
+ */
+ private static int[][] toHistogram(byte[][] matrix) {
+ int rows = matrix.length;
+ int cols = matrix[0].length;
+ int[][] histogram = new int[rows][cols];
+ for (int h=0; h < cols; h++) {
+ if (matrix[0][h] == 0) {
+ histogram[0][h] = 1;
+ }
+ }
+ for (int w=1; w < rows; w++) {
+ for (int h=0; h < cols; h++) {
+ if (matrix[w][h] == 1) {
+ continue;
+ }
+ histogram[w][h] = histogram[w-1][h] + 1;
+ }
+ }
+ return histogram;
+ }
+}